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10x^2-50x=360
We move all terms to the left:
10x^2-50x-(360)=0
a = 10; b = -50; c = -360;
Δ = b2-4ac
Δ = -502-4·10·(-360)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-130}{2*10}=\frac{-80}{20} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+130}{2*10}=\frac{180}{20} =9 $
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